The Acceleration of a Bus Is Given by Ax(T)=ãžâ±t, Where ÞⱠ= 1.18 M/s3 Is a Constant.

Problem 52E

Problem 52E

The acceleration of a omnibus is apt past ax ( t ) = αt , where α  = 1.2 m/s3. (a) If the bus's velocity at clock t  = 1.0 s is 5.0 m/s, what is its velocity at time t  = 2.0 s? (b) If the motorcoach's position at time t  = 1.0 s is 6.0 m, what is its position at time t  = 2.0 s? (c) Sketch ax - t , vx - t , and x - t  graphs for the motion.

Step-by-Step Solution:

Step 1 of 3

Solution 52E

(a) The acceleration is acknowledged by

 ….(1)

We can sustain the velocity of the particle away integrating the above equation with respect to . Then integrating the above equation with respect to , we have

Where C is the constant quantity of integration and can be measured from the first condition.

Now the initial condition for velocity is at t=1.0 s, . Victimisation the above precondition we have

So the function for velocity leave be

 …. (2)

Straight off if we put , and then we will have

Hence the velocity of the bus subsequently 2.0 s is 6.8 m/s.

(b) We will fix the situation of the bus past integrating the equating (2) with respectfulness to time. Thu the billet of the bus is given away

Here D is the constant of integration and can be calculated from the initial condition. The initial condition is at  s, . Thence using this condition we experience

Indeed the position of the bas throne Be written as

Now putt the value , we possess

Hence the position of the bus at  is 11.8 m.

(c) The  chart is shown below.

graph1.png

The velocity vs time chart is shown infra:

v-vs-t.png

And the position vs time graph is shown below.

x-vs-t.png

Textbook: Sears and Zemansky's University Natural philosophy with Modern Physics
Edition: 13

Source: Hugh D. Schoolboyish; Roger A. Freedman; A. Lewis Gerald Rudolph Ford
ISBN: 9780321696861

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